用SWIFT将字符串转换为INT
用SWIFT将字符串转换为INT
@IBOutlet var txtBox1 : UITextField@IBOutlet var txtBox2 : UITextField@IBOutlet var txtBox3 :
UITextField@IBOutlet var lblAnswer : UILabel@IBAction func btn1(sender : AnyObject) {
let answer1 = "The acceleration is"
var answer2 = txtBox1
var answer3 = txtBox2
var answer4 = txtBox3
慕村9548890浏览 3910回答 3
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沧海一幻觉
基本想法，请注意，这只适用于SWIFT 1.x(退房ParaSara的回答要了解它在SWIFT 2.x中的工作方式)： // toInt returns optional that's why we used a:Int? let a:Int? = firstText.text.toInt() // firstText is UITextField let b:Int? = secondText.text.toInt() // secondText is UITextField // check a and b before unwrapping using ! if a && b { var ans = a! + b! answerLabel.text = "Answer is \(ans)" // answerLabel ie UILabel } else { answerLabel.text = "Input values are not numeric" }SWIFT 4更新...let a:Int? = Int(firstText.text) // firstText is UITextFieldlet b:Int? = Int(secondText.text) // secondText is UITextField... -
白板的微信
更新SURVER 2.0的答案 :toInt()方法给出了一个错误。因为，在SWIFT 2.x中，.toInt()函数从字符串中删除。在替换中，Int现在有一个接受字符串的初始化器：let a:Int? = Int(firstText.text) // firstText is UITextField let b:Int? = Int(secondText.text) // secondText is UITextField -
慕容708150
myString.toInt()-将字符串值转换为int。SWIFT 3.x如果在字符串中隐藏了整数，则可以使用整数的构造函数进行转换，如下所示：let myInt = Int(textField.text)与其他数据类型(浮点和双)一样，也可以通过使用NSString进行转换：let myString = "556"let myInt = (myString as NSString).integerValue
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iOS
Swift