【Python 字符串】-判断一个字符串是否包含某个指定的字符串

"""check whether some letters lies in one word"""
word = "paramount"
letters = 'para'
if letters in word.lower():
    print("True")
    print(letters)

print("#check if two words share common letters, if so, print them out.")
inter = set(word).intersection(set(letters))
print(inter)

print("#Member Operator in")

str = "Sstring test using member operator in string test using member operator in"
member1 = "str"
member2 = "usi"
print(member1 in str, member2 in str)
print("mem" not in str)

print("#work wtih the methods of string object: find(), rfind(), index(), rindex()")
"""
find()和index()的区别:
方法	区别
 find() 	获取值时,如果要查找的值不存在,会返回-1
 index() 	获取值的索引时,如果不存在值,会报错
 """
print(str.find(member1))
print(str.find(member2))

print(str.rfind(member1))
print(str.rfind(member2))

print(f"index(): {str.index(member1)}")
print(f"index(): {str.index(member2)}")

print(f"rindex(): {str.index(member1)}")
print(f"rindex(): {str.index(member2)}")

str = "I like China"
print(f"count(): {str.count(member1)}")
print(f"count(): {str.count(member2)}")

python判断字符串包含关系

转自---http://blog.csdn.net/yl2isoft/article/details/52079960

1.使用成员操作符 in

>>> s='nihao,shijie'
>>> t='nihao'
>>> result = t in s
>>> print result
True

2.使用string模块的find()/rfind()方法

>>> import string
>>> s='nihao,shijie'
>>> t='nihao'
>>> result = string.find(s,t)!=-1
>>> print result
True
>>> result = string.rfind(s,t)!=-1
>>> print result
True 

3.使用string模块的index()/rindex()方法 
index()/rindex()方法跟find()/rfind()方法一样,只不过找不到子字符串的时候会报一个ValueError异常。

import string

def find_string(s,t):
    try:
        string.index(s,t)
        return True
    except(ValueError): 
        return False

s='nihao,shijie'
t='nihao'
result = find_string(s,t)
print result  #True

 

4.使用字符串对象的find()/rfind()、index()/rindex()和count()方法

>>> s='nihao,shijie'
>>> t='nihao'
>>> result = s.find(t)>=0
>>> print result
True
>>> result=s.count(t)>0
>>> print result
True
>>> result=s.index(t)>=0
>>> print result
True

参考链接:https://www.cnblogs.com/johnson-yuan/p/7910087.html
posted @ 2022-03-29 12:14  易点灵通  阅读(946)  评论(0编辑  收藏  举报