python wmi 配置_StartMode为“自动(延迟启动)”的Windows服务的Python WMI查询

任何人都有一个很好的技巧(用Python)来检测配置了启动类型为“自动(延迟启动)”的Windows服务？

我认为WMI会是一条路，但配置为“自动”和“自动(延迟启动)”的服务都显示为“自动”的启动模式。

例如，在使用Services.msc的本地Windows 7框中，我看到“Windows Update”配置为“自动(延迟启动)”，但WMI仅显示为“自动”：

>>> c = wmi.WMI()

>>> local = c.Win32_Service(Caption='Windows Update')

>>> len(local)

1

>>> print local[0]

instance of Win32_Service

{

AcceptPause = FALSE;

AcceptStop = TRUE;

Caption = "Windows Update";

CheckPoint = 0;

CreationClassName = "Win32_Service";

Description = "Enables the... ...(WUA) API.";

DesktopInteract = FALSE;

DisplayName = "Windows Update";

ErrorControl = "Normal";

ExitCode = 0;

Name = "wuauserv";

PathName = "C:\\Windows\\system32\\svchost.exe -k netsvcs";

ProcessId = 128;

ServiceSpecificExitCode = 0;

ServiceType = "Share Process";

Started = TRUE;

StartMode = "Auto";

StartName = "LocalSystem";

State = "Running";

Status = "OK";

SystemCreationClassName = "Win32_ComputerSystem";

SystemName = "MEMYSELFANDI";

TagId = 0;

WaitHint = 0;

};

>>> local[0].StartMode

u'Auto'我欢迎任何建议。

干杯，

抢